Baliani, Giovanni Baptista De Motu Naturali Gravium Solidorum Ioannis Baptistae Baliani 1638

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<chap> <p type="head"> <s id="s.000178">PROPOSITIO XIV. PROBL. VII.<lb/>
</s> </p>

<subchap1> <p> <s id="s.000179">Data linea perpendiculari, per quam grave descendat,<lb/>
cui annectatur linea, seu planum declinans; in decli-<lb/>
nante reperire punctum, quo grave perveniat eo<lb/>
tempore, quo pertransiverit perpendicularem.<lb/>
</s> </p>

</subchap1> <p> <s id="s.000180">Sit triangulum ABC orthogonaliter erectum super pla<lb/>
no orizontali BC, cuius latus AB intelligatur sit linea perpendicu-<lb/>
laris, per quam grave descendat, &amp; latus AC sit planum<lb/>
inclinatum.<lb/>
</s> </p>

<p> <s id="s.000181">Oportet in plano AC reperire punctum quo grave perveniat<lb/>
eodem tempore, quo in B.<lb/>
</s> </p>

<p> <s id="s.000182">Fiat ut AC ad AB, ita AB ad tertiam AD, &amp; D erit pun-<lb/>
ctum quaesitum.<lb/>
</s> </p>

<p> <s id="s.000183">Quoniam ut AC ad AD, ita quadratum AC ad quadra-<lb/>
tum AB<arrow.to.target n="marg29"/>, &amp; ut AC ad AD, ita quadratum temporis A<lb/>
C ad quadratum temporis AD<arrow.to.target n="marg30"/>, ergo ut quadratum A<lb/>
C ad quadratum AB, ita quadratum temporis AC ad qua-<lb/>
dratum temporis AD<arrow.to.target n="marg31"/>, ergo ut AC ad AB, ita tempus<lb/>
AC ad tempus AD<arrow.to.target n="marg32"/>, sed ut AC ad AB, ita tempus AC ad<lb/>
tempus AB<arrow.to.target n="marg33"/>, ergo tempus AB est aequale tempori AD.<lb/>
</s> <s id="s.000184">Quod, &amp;c.<lb/>
</s> </p>

<p type="margin"> <s id="s.000185"><margin.target id="marg29"/>Per 19.<lb/>
Sexti.<lb/>
</s> <s id="s.000186"><margin.target id="marg30"/>Per cor.<lb/>
7. hujus.<lb/>
</s> <s id="s.000187"><margin.target id="marg31"/>Per 11.<lb/>
Quinti.<lb/>
</s> <s id="s.000188"><margin.target id="marg32"/>Per 22.<lb/>
Sexti.<lb/>
</s> <s id="s.000189"><margin.target id="marg33"/>Per 11.<lb/>
hujus.<lb/>
</s> </p>

</chap>